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144x^2+218x+21=0
a = 144; b = 218; c = +21;
Δ = b2-4ac
Δ = 2182-4·144·21
Δ = 35428
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{35428}=\sqrt{4*8857}=\sqrt{4}*\sqrt{8857}=2\sqrt{8857}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(218)-2\sqrt{8857}}{2*144}=\frac{-218-2\sqrt{8857}}{288} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(218)+2\sqrt{8857}}{2*144}=\frac{-218+2\sqrt{8857}}{288} $
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